flutter dart json decode encode

Very Important!

  
{"107年工作":{"zhangqi":[{"name":"王大明1"},{"name":"孫小明1"}],"chaojiangeren":[{"name":"nnn1","addr":"aaa1"},{"name":"nnn2","addr":"aaa2"}]},"108年法會":{"zhangqi":[{"name":"王大明1"},{"name":"孫小明1"}]}}  

zhangqi : [ …. ]
chaojiangeren: [ …. ]

zhangqi : [ {….}, {….} ]
chaojiangeren: [ {….}, {….} ]

Can’t have \' or \"

If have this, json.decode can’t List

List => List
List => List

  
List<ItemName> zhangqi = List<ItemName>();  
zhangqi.add(new ItemName(name:"王大明1"));  
zhangqi.add(new ItemName(name:"孫小明1"));  
  
List<ItemNameAddr> chaojiangeren = List<ItemNameAddr>();  
chaojiangeren.add(new ItemNameAddr(name:"nnn1", addr:"aaa1"));  
chaojiangeren.add(new ItemNameAddr(name:"nnn2", addr:"aaa2"));  
  
  
class ItemName {  
  String name;  
  
  ItemName({ this.name }) ;  
  ItemName.fromJson(Map<String, dynamic> json) : name = json['name'];  
  Map toJson() => {"name": name };  //給json.encode使用，沒有的話，會錯誤  
}  
  
class ItemNameAddr {  
  String name;  
  String addr;  
  
  ItemNameAddr({ this.name, this.addr }) ;  
  ItemNameAddr.fromJson(Map<String, dynamic> json) : name = json['name'], addr = json['addr'];  
  Map toJson() => {"name": name, "addr": addr};  //給json.encode使用，沒有的話，會錯誤  
}  
  
Future<List<ItemName>> getListItemName(List maps) async {  
  return new List<ItemName>.generate(maps.length, (i) {  
    return ItemName(  
      name: maps[i]['name'],  
    );  
  });  
}  
  
Future<List<ItemNameAddr>> getListItemNameAddr(List maps) async {  
  return new List<ItemNameAddr>.generate(maps.length, (i) {  
    return ItemNameAddr(  
      name: maps[i]['name'],  
      addr: maps[i]['addr'],  
    );  
  });  
}